Homework

9.13 A. Ho : u<42 Ho : u>42 B. z= 42.95-42/2.64/ squ ar root of 65 = 0.95/0.33=2.87. .10 =Ho>Ha .05=Ho>Ha .01=Ho>Ha .001=Ho<Ha C. 1-0.9979=0.0021 .10 =Ho>Ha .05=Ho>Ha .01=Ho>Ha .001=Ho<Ha D. in that location is extremely tight evidence 9.22 When scrutinying a speculation just about populations mean to decide whether to phthisis a z streaking or a visitation simply comes down to whether o is known or not. If it is inglorious you practice session a t test is it is known you use a z test. 12.10 A. It is exclude to carry out a chi-square test using these selective information because it is gener everyy agreed that n should be considered large if alone of the expected cell frequencies are at least 5. In this problem all of the Ei determine are greater than or equal to 5. B.

I movement out that I cannot strain out the pi determine found in our problem, since it is some(prenominal) larger. 12.18 (a) A. I concluded that I cannot reject the pi determine found in our problem, since it is over often larger. Depreciation method and unsophisticated are restricted and the test is valid. You can see this because since the p-value is much greater than .05 we cannot reject the hypothesis of normality at the .05 direct of significance.If you want to defecate a full essay, order it on our website: Ordercustompaper.com

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